Model 5 Find New Average From Error Practice Questions Answers Test With Solutions & More Shortcuts

Answer: (c)

Weight of the new oarsman = 60 + 8 × $3/2$

= 60 + 12 = 72 kg

Aliter : Using Rule 18,

Here, N = 8, T = 60, t = $3/2$

Weight of new man = T + Nt

= 60 + 8 × $3/2$

= 60 + 12 = 72

Answer: (a)

Required Average

= ${100 × 46 – 61 – 34 + 16 + 43}/90$

= ${4600 – 36}/90$ = $4564/90$ = 50.7

Answer: (d)

According to question,

Total marks = 71 × 14 = 994

Correct total marks

= 994 + (56 – 42) + (32 – 74)

= 994 + 14 – 42 = 966

∴ Required average = $966/14$ = 69

Aliter : Using Rule 27,

If the average of n numbers is m later on it was found that two numbers a and b misread as p and q.

The correct average = m +${\text"(a+b-p-q)"}/ \text"n"$.

Here n = 14, m = 71

a = 56, b = 42

p = 32, q = 74

Correct Average

= m +${\text"(a+b-p-q)"}/ \text"n"n$

= 71 +${(56+ 32- 42- 74)}/14$

= 71 -$28/14$

= 71 – 2 = 69

Answer: (d)

Required average

= 30+${(28+31-82-13)}/50$

= 30 $(-36/50)$

= 30 – 0.72 = 29.28

Aliter : Using Rule 27,

If the average of n numbers is m later on it was found that two numbers a and b misread as p and q.

The correct average = m +${\text"(a+b-p-q)"}/ \text"n"$.

Here, n = 50, m = 30

a = 28, b = 31

p = 82, q = 13

Correct Average = m + ${\text"(a+b-p-q)"}/ \text"n"n$

= 30 +${(28+31-82-13)}/50$

= 30 +$({59-95}/50)$

= 30 -$36/50$

= 30 – 0.72 = 29.28

Answer: (d)

Correct sum of 100 items

= 30 × 100 – 32 – 12 + 23 + 11

= 3000 – 44 + 34 = 2990

∴ Required average = 2990 100 = 29.9